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The rate of a reaction doubles when its temperature changes form `300 K` to `310 K`. Activation energy of such a reaction will be: `(R = 8.314 JK^(-1) mol^(-1) and log 2 = 0.301)`A. `48.6 KJ mol^(-1)`B. `58.5 KJ mol^(-1)`C. `60.5 KJ mol^(-1)`D. `53.6 KJ mol^(-1)` |
Answer» Correct Answer - D | |