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The rate of a reaction doubles when its temperature changes form `300 K` to `310 K`. Activation energy of such a reaction will be: `(R = 8.314 JK^(-1) mol^(-1) and log 2 = 0.301)`A. 4.92 KB. 9.84 KC. 19.67 KD. 2.45 K

Answer» Correct Answer - A


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