1.

The rate of a reaction is doubled for every 10^(@)C rise in temperature . The increase in reaction rate as a result of temperature rise from 10^(@) C to 100^(@)C is

Answer»

112
512
400
614

Solution :`(k_(t) + 10)/(k_(t)) = (r_(t) + 10)/(r_(t)) = 2`.
For an increase to `90^(@)C` i.e. 9 times , the rate increases by `2^(9)` times i.e. 512.


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