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The rate of a reaction quadruples when temperature charges from 293 K to 312K, Calculate the energy of activation of the reaction assuming that it does not charge with temperature. |
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Answer» According to Arrhenius equation `log ""(k_(2))/(k_(1))=(E_(a))/(2.303)[(1)/(T_(1))-(1)/(T_(2))],` Given `[therefore T_(i) =293 K, T_(2) -T_(1) =20K]` `log ""(4)/(1) =(E_(a))/(2.303 xx(8.314 J mol ^(-1)k^(-1)))xx(20)/(293xx313)` `E_(a)=(0.6021xx2.303xx8.314xx293xx313)/(20) J mol ^(-1)` `=52863mol ^(-1)` `E_(a)=52.863kJ mol ^(-1).` |
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