1.

The rate of a reaction quadruples when the tamperature changes from 300 to 310k. The activation energy of this reaction is : (Assume activation energy and pre-exponential factor are independent of temperature , In2=0.693, R=8.314J*mol^(-1)*K^(-1))

Answer»

`107.2kJ*mol^(-1)`
`53.6kJ*mol^(-1)`
`26.8kJ*mol^(-1)`
`214.4kJ*mol^(-1)`

SOLUTION :`In(k_(1))/(k_(2))=(E_(a))/(R)[(1)/(T_(1))-(1)/(T_(2))]`
`IN4=(E_(a))/(8,314)((310-300)/(310times300))`
`2In2=(E_(a))/(8,314)((310-300)/(310times300))`
`E_(a)=107.2kJ*mol^(-1)`


Discussion

No Comment Found

Related InterviewSolutions