1.

The rate of change of velocity is 1ms^(-2)when a force is applied on the body of mass 75 gm the force is

Answer»

75 N
0.75 N
0.075 N
`0.75 XX 10^(-3) N`

Solution :Force is GIVEN by
`F= ma`
` = 75gm xx1 cm s^(-2) = 75xx 10^(-3) xx 1 = 75xx 10^(-3) = 0.075N`


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