The rate of coolingof water in a calorimete is one-tenth of a degree per second when itstemperature is 40^(@)Cabove thatof the sorroudings . Whatis the rateof cooling andheatlost persecond whenthe excess temperatuer over thesurrodings is 30^(@)C ? Thermalcapacityof waterand calorimater is 4600 J//""^(@)C

The rate of coolingof water in a calorimete is one-tenth of a degree p

1.	The rate of coolingof water in a calorimete is one-tenth of a degree per second when itstemperature is 40^(@)Cabove thatof the sorroudings . Whatis the rateof cooling andheatlost persecond whenthe excess temperatuer over thesurrodings is 30^(@)C ? Thermalcapacityof waterand calorimater is 4600 J//""^(@)C
Answer» Solution :Rate of cooling, `(d theta)/(dt) prop`excess temperatureover the surroudings. In the first CASE `(1)/(10) prop 40`, In the second case `(d theta)/(dt) prop 30` . DIVING`(dtheta)/(dt) //(1)/(10) =(30)/(4) ""therefore (d theta)/(dt) = (3)/(4 xx 10)=(3)/(40)""^(@)C// SEC ` Rateof heat RADITION ` = ms ( d theta)/(dt) `= Thermal capacity `xx ( d theta)/(dt) = 4600 xx (3)/(40) = 345J//sec`