The rate of diffusion of helium and methane under identical conditions

1.	The rate of diffusion of helium and methane under identical conditions of temperature and pressure will be
Answer» Answer:2:1 Explanation: r1/r2=(m2/m1)^1/2 r = rate of diffusion m = MOLECULAR weight ATQ: r1/r2 = (16/4)^1/2 = 4:1 MW of CH4 =16 MW of HE2 =4

The rate of diffusion of helium and methane under identical conditions of temperature and pressure will be

Answer»

Answer:2:1

Explanation: r1/r2=(m2/m1)^1/2

r = rate of diffusion

m = MOLECULAR weight

ATQ:

r1/r2 = (16/4)^1/2

= 4:1

MW of CH4 =16

MW of HE2 =4