1.

The rate of effusion of a particular gas whas measured to be 40ml/min. Under same condition the rate of effusion of pure methane was 20ml/min. Then find molar mass of gas.

Answer»

4amu
2amu
4GM
2gm

Solution :`(r_(CH_(4)))/(r_(GAS))=sqrt((M_(gas))/(16))=(20)/(40)=(1)/(2)`
`M_(gas)=4gm`


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