Saved Bookmarks
| 1. |
The rate of effusion of a particular gas whas measured to be 40ml/min. Under same condition the rate of effusion of pure methane was 20ml/min. Then find molar mass of gas.A. 4amuB. 2amuC. 4gmD. 2gm |
|
Answer» `(r_(CH_(4)))/(r_(gas))=sqrt((M_(gas))/(16))=(20)/(40)=(1)/(2)` `M_(gas)=4gm` |
|