The rate of flow in stream with 20% O2 and 80% CO2 is 5 mole/hr, the contained was initially filled with 3 mole of O2, what will be the percentage of O2 in product stream?(a) 12.5(b) 25(c) 37.5(d) 50I had been asked this question by my college director while I was bunking the class.This is a very interesting question from Multiple Component Systems topic in section Introduction to Material Balances of Basic Chemical Engineering

The rate of flow in stream with 20% O2 and 80% CO2 is 5 mole/hr, the c

1.	The rate of flow in stream with 20% O2 and 80% CO2 is 5 mole/hr, the contained was initially filled with 3 mole of O2, what will be the percentage of O2 in product stream?(a) 12.5(b) 25(c) 37.5(d) 50I had been asked this question by my college director while I was bunking the class.This is a very interesting question from Multiple Component Systems topic in section Introduction to Material Balances of Basic Chemical Engineering
Answer» Right CHOICE is (d) 50 The EXPLANATION is: Percentage of O2 = 4/(4 + 4)*100 = 50%.

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