The rate of flow in stream with 40% O2 and 60% CO2 is 10 mole/hr, the contained was initially filled with 6 mole of O2, what will be the percentage of O2 in product stream?(a) 12.5(b) 25(c) 50(d) 62.5I had been asked this question in class test.The doubt is from Multiple Component Systems in chapter Introduction to Material Balances of Basic Chemical Engineering

The rate of flow in stream with 40% O2 and 60% CO2 is 10 mole/hr, the

1.	The rate of flow in stream with 40% O2 and 60% CO2 is 10 mole/hr, the contained was initially filled with 6 mole of O2, what will be the percentage of O2 in product stream?(a) 12.5(b) 25(c) 50(d) 62.5I had been asked this question in class test.The doubt is from Multiple Component Systems in chapter Introduction to Material Balances of Basic Chemical Engineering
Answer» CORRECT ANSWER is (d) 62.5 To EXPLAIN I would say: PERCENTAGE of O2 = 10/(10 + 6)*100 = 62.5%.

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