1.

The rate of formation of a dimer in a second order reaction 7.5xx10^(-3) "mol L"^(-1)s^(-1)at 0.05"mol L "^(--1)monomer concentration. Calculate the rate constant.

Answer»

Solution :LET us consider the DIMERISATION of a MONOMER M .
`2M rarr(M)_2`
Rate `=k[M]^n`
Given that n = 2 [ M] `=0.05 "mol L"^(-1)`
Rate `=7.5xx10^(-3) "mol L"^(-1)s^(-1)`
`k=("Rate")/([M]^n)impliesk=(7.5xx10^(-3))/((0.05)^2)=3 "mol"^(-1)Ls^(-1)`


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