1.

The rate of reaction becomes 2 times for every 10^@C rise in temperature. How the rate of reaction will increase when temperature is increased from 30^@C" to" 80^@C ?

Answer»

16
32
64
128

Solution :`(k_(t + 10))/k_t=(r_(t+ 10))/r_1=2`,
For an increase of temperature to `50^@C`, i.e., 5 times, the rate increases by `2^5` times, i.e., 32 times.


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