1.

The rate of reaction between two reactants A andB decreases by a factor of 4 if the concentration of reactant B is doubled . The order of this reaction with respect to reactant B is

Answer»

-1
-2
1
2

Solution :R = `K[B]^(n) , (1)/(4) R = k [2B]^(n) , 4 = ((1)/(2))^(n) , 4 = 2^(-n) , n = -2`.


Discussion

No Comment Found