The rate of reaction is doubled when the temperature changes from 27^@ – InterviewSolution

1.	The rate of reaction is doubled when the temperature changes from 27^@C to 37^@C. Calculate the energy of activation.
Answer» SOLUTION :We KNOW that` "log" K_2/K_1=E_a/(2.303R)[1/T_1-1/T_2]`Substituting the VALUES, `"LOG2"=E_a/(2.303xx8.314)[1/300-1/310]` `E_a=(0.3010xx2.303xx8.314xx300xx310)/10=535986.5=53.5kj=535986.5=53.5kj`

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