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The rate of the reaction : 2N_(2)O_(5)rarr4NO_(2)+O_(2) can be written in three ways. (1)/(4)(-d[N_(2)O_(5)])/(dt)=k[N_(2)O_(5)],(d[NO_(2)])/(d)=k'[N_(2)O_()](d[NO_(2)])/(d)=k'[N_(2)O_(5)] The relationship between K and K' and between K' and K' becomes |
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Answer» `K'=2K , K''=K'` `-(1)/(2)(d[N_(2)O_(5)])/(dt)+(1)/(4)(d[NO_(2)])/(dt)=(d[O_(2)])/(dt)` |
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