1.

The rate of the reaction 2N_(2)O_(5) to 4 NO_(2) + O_(2) can be written in three ways (-d [N_(2)O_(5)])/(dt) = k [N_(2)O_(5)] (d [NO_(2)])/(dt) = k' [N_(2)O_(5)] (d[O_(2)])/(dt ) = k'' [N_(2)O_(5)] The relationship between k and k' and between k and k'' are

Answer»

k' = 2K , k''= 2k
k' = k , k''= k
k' = 2k , k''= k
k' = 2k , k''= k/2

Solution :`-(1)/(2) (d(N_(2)O_(5)))/(DT) = (1)/(4) (d(NO_(2)))/(dt) = (d(O_(2)))/(dt)`
`(1)/(2) k (N_(2)O_(5)) = (1)/(2) k' (N_(2)O_(5)) = k'' (N_(2)O_(5))`
`(k)/(2) = (k')/(4) = k'' implies k' = 2k , k'' = (k)/(2)`.


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