1.

The rate of the reaction A to products , at the intitial concentrations of 3.24 xx 10^(-2)M is nine times its rate at constant initial concentration of 1.2 xx 10^(-3)M . The order of the reaction is

Answer»

`(1)/(2)`
`(3)/(4)`
`(3)/(2)`
`(2)/(3)`

Solution :9r = `k (3.24 xx 10^(-2))^(ALPHA ) "" …. (i)`
`r = k(1.2 xx 10^(-3))^(alpha) "" …. (ii)`
DIVIDE EQ. (i) by (ii)
`(9r)/(r) = (k(3.24 xx 10^(-2))^(alpha))/(k (1.2 xx 10^(-3))^(alpha)) implies 3^(2) = 3^(3alpha)`
`THEREFORE alpha = (2)/(3)`.


Discussion

No Comment Found

Related InterviewSolutions