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The rate of the reaction A toProducts, at the initial concentration of 3.24xx10^(-2) M is nine times its rate at another initial concentration of 1.2xx10^(-3) M. The order of the reaction is |
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Answer» `(1)/(2)` `r = k(1* 2 xx 10^(-3))^(n)""…(ii)` DIVIDING (i) by (ii), ` 9 = ((3.24 xx 10^(-2))/(1*2 xx 10^(-3)))^(n) or 9 = (27)^(n)` or `(3)^(2) = (3^(3))^(n) = (3)^(3N).` Hence, `3 n = 2 or n = 2//3`. |
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