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The rate of the reaction x+2yrarr product is 4xx10^(-3) " mol L"^(-1)s^(-1) , if [x] = [y] =0.2 M and rate constant at 400K is 2xx10^(-2)s^(-1) , what is the overall order of the reaction. |
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Answer» Solution :Rate `=K[x]^n[y]^m` `4xx10^(-3)"mol"L^(-1)s^(-1)=2xx10^(-2)s^(-1)(0.2 "mol L"^(-1))^n(0.2 "mol L"^(-1))^m` `(4xx10^(-3)"mol L"^(-1)s^(-1))/(2xx10^(-2)s^(-1))=(0.2)^(n+m)("mol L"^(-1))^(n+m)` `2.0("mol L"^(-1))=(0.2)^(n+m)("mol L"^(-1))^(n+m)` Comparing the powers on both sides , the overall order of the REACTION n + m = 1 |
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