1.

The rate of the reaction X to Y becomes 8 times when the concentration of the reactant 'X' is doubled . The rate law of the reaction is ………..

Answer»

`- (d [X])/(dt) = k [X]^(2)`
`- (d [x])/(dt) = k[X]^3`
`- (d[x])/(dt) = k[X]^(4)`
`- (d[x])/(dt) = k[X]^(8)`

SOLUTION :`- (d[x])/(dt) = k[X]^(3)`


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