1.

the rate ofa first- orderreactionis 0.04 molL^(-1) s^(-1)at 10sec and 0.03 mol L^(-1) S^(-1)at 20 sec afterinitiationof thereaction the half-lifeperiod of the reaction is

Answer»

`34.1s`
44.1 s
54.1s
24.1

Solution :Givenorder of reaction =1
Rateof reaction at 10 s=0.04 MOL `L^(-1)S^(-1)`
rateof reactionat 20s=0.03 `mol L^(-1)S^(-1)`
` therefore ` half - lifeperiod `(t_(1//2))=?`
we have the equation forrate- constant 'K' in firstorderreaction .
`K =(2303)/(t) log""(A_(t))/(A_(0))=(2.303)/(105 ) log""(0.04)/(0.03)`
` =(2.303)/(105)xx0.124`
`k=0.028s^(-1)`
weknow that
`t_(1//2)=(0.693)/(k) =(0.693)/(0.028773391S^(-1))`
`=24.14 s=24.1S`


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