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The rates of most reactions double when their temperature is raised from 298 K to 308 K. Calculate their activation energy. |
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Answer» SOLUTION :`logK_2/K_1=E_a/(2.303R)[1/T_1-1/T_2]` `E_a=(2.303xx8.314xx298xx308xx0.3010)/1000` `E_a`=52.89 KJ/mol |
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