1.

The ratio between a two-digit number and the sum of the digits of that number is 4 : 1. If the digit in the unit's place is 3 more than the digit in the ten’s place, what is the number?

Answer»

Let the ten's digit be x. 

Then, unit's digit = (x + 3). 

Sum of the digits = x + (x + 3) = 2x + 3. 

Number = 10x + (x + 3) = 11x + 3. 

11x +3 / 2x + 3 = 4 / 1 

=> 11x + 3 = 4 (2x + 3) 

=> 3x = 9 

=> x = 3. 

 Hence, required number = 11x + 3 = 36.



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