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The ratio between the radius of the base and the height of the cylinder is 2:3. If its volume is 1617 `cm^3` , the total surface area of the cylinderical isA. `308 cm^(2)`B. `462 cm^(2)`C. `540 cm^(2)`D. `770 cm^(2)` |
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Answer» Correct Answer - D Let the radius be 2x cm and the height be 3x cm. Then, volume `= pi xx (2x)^(2) xx 3x = (22)/(7) xx 12 xx x^(3)` `:. (22)/(7) xx 12 xx x^(3) = 1617 rArr x^(3) = (1617 xx (1)/(12) xx (7)/(22)) = (49 xx 7)/(8) = ((7)/(2))^(3)` `rArr x = (7)/(2) rArr r = 7 cm and h = (21)/(2) cm` `:.` total surface area `= 2pi rh + 2pi r^(2) = 2pi r (h + r)` `= {2 xx (22)/(7) xx 7 xx ((21)/(2) + 7)} cm^(2) = 770 cm^(2)` |
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