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The ratio of `11^(th)` term from the beginning and `11^(th)` term the end in the expansion of `(2x-(1)/(x^(2)))^(25) " is " -`A. `x^(15)`B. `-2^(5) x^(15)`C. `2^(15)x^(5)`D. `2^(5)x^(-15)` |
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Answer» Correct Answer - B `T_(11"staring") =25 C_(10) 2^(15)((1)/(x^(5)))` `T_(11"ending") = T_(16("starting"))` `=-.^(25)C_(15)2^(10)((1)/(x^(20)))` `"then" (T_(11("starting")))/(T_(11("ending")))=-2^(5) x^(15)` |
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