1.

The ratio of 4^(th) term and 5^(th) term in the expansion of (x+(sinx)/(x))^(6) is (16)/(3pi^(2)), then x is equal to (1) (pi)/(2) (2) -(pi)/(2) (3) (pi)/(3) (4) Both (1) & (2)

Answer»

Solution :Answer (1)
`T_(4)=.^(6)C_(3)*x^(3)*((sinx)/(x))^(3)`
`T_(5)=.^(6)C_(4)*x^(4)*((sinx)/(x))^(2)`
Now,
`(T_(4))/(T_(5))=(16)/(3PI^(2))`
`implies(.^(6)C_(3)SIN^(3)x)/(.^(6)C_(4)x^(2)*sin^(2)x)=(16)/(3pi^(2))`
`implies(20sinx)/(15x^(2))=(16)/(3pi^(2))`
`implies(sinx)/(x^(2))=(16xx15)/(20xx3pi^(2))=(4)/(pi^(2))`
`impliesx=(pi)/(2)`


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