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The ratio of altitudes of two similar triangles is 4 : 9, then ratio of their areas is (A) 2 : 3 (B) 4 : 9 (C) 81 : 16(D) 16 : 81 |
Answer» Correct option is (D) 16 : 81 The ratio of areas of similar triangle is square of the ratio of corresponding sides (or altitude) of similar triangle. \(\therefore\) The ratio of areas of given similar triangle \(=(\frac49)^2\) \(=\frac{16}{81}=16:81\) Correct option is: (D) 16 : 81 |
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