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The ratio of amounts of H_(2)S needed to precipitate all the metal ions from 100 ml of 1 M AgNO_(3) and 100 ml of 1 M CuSO_(4) will be |
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Answer» `1:2` `2KMnO_(4)+3H_(2)SO_(4) to K_(2)SO_(4)+2MnSO_(4)+3H_(2)O+5(O)` `2xx158=(316xx8)/(80)=31.6` So, equivalent wt. of `KMnO_(4)` in acidic medium is `=31.6`gm |
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