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The ratio of areas of two similar triangles is 1: 2, then the ratio of their altitudes is (A) 1 : √2 (B) 1 : 2 (C) 2 : 1 (D) √2 : 1 |
Answer» Correct option is (A) 1 : √2 The ratio of altitudes of similar triangle = (The ratio of areas of similar triangle\()^\frac12\) \(=(\frac12)^\frac12=\sqrt{\frac12}\) \(=\frac1{\sqrt2}=1:\sqrt2\) Correct option is: (A) 1 : √2 |
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