1.

The ratio of average speed of an oxygen molecular to the r.m.s. speed of a N_(2) molecular at the same temperature is :

Answer»

`((3PI )/( 7) )^(1//2)`
`(( 7)/( 3pi ))^(1//2)`
`((3)/( 7pi ))^(1//2)`
`((7pi)/( 3))^(1//2)`

Solution :`u_(av)` of `O_(2) = sqrt((8RT)/( M)) = sqrt(( 8 RT)/( pi xx 32))`
`u_("rms") ` or `N_(2) = sqrt(( 3RT)/( M)) = sqrt(( 3RT)/( 28))`
`( u_(av))/( u_("rms")) = sqrt((8RT)/(pi xx 32))xxsqrt((28)/( 3RT)) = (7^(1/2))/( 3pi)`


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