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The ratio of closed packed atoms to tetrahedral holes in cubic close packing is `:`A. `1:1`B. `1:2`C. `1:3`D. `2:1`

Answer» Correct Answer - B
Every constituent has two tetrahedral voids in ccp lattice atoms `=8xx(1)/(8)+6xx(1)/(2)=4`
`therefore` Tetrahedral void `=4xx2=8`, thus ratio `=4:8::1:2`.


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