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The ratio of coefficient of `HNO_(3), Fe(NO_(3))_(2)` and `NH_(4)NO_(3)` in the following redox reaction `Fe + HNO_(3) rarr Fe (NO_(3))_(2) + NH_(4)NO_(3) + H_(2)O` are respectivelyA. `1:10:4`B. `10:4:1`C. `4:10:1`D. `10:1:4` |
Answer» Correct Answer - B `Fe+HNO_(3)rarrFe(NO_(3))_(2)+NH_(4)NO_(3)+H_(2)O` Half reaction method : `Fe rarr Fe^(2+)+2e^(-)..(1)xx4` `NO_(3)^(-)+10H^(o+)+8e^(Theta)rarrNH_(4)^(o+)+3H_(2)O.....(2)` Equation `(1)xx4+(2)` `4Fe+NO_(3)^(-)+10H^(o+)rarr4fe^(2+)+NH_(4)^(o+)+3H_(2)O` `"Add"^(n)` of spectator ion `4Fe+10HNO_(3)rarr4Fe(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O` |
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