The ratio of de - Broglie wavelength of `alpha `- particle to that of a proton being subjected to the same magnetic field so that the radii of their path are equal to each other assuming the field induction vector `vec(B)` is perpendicular to the velocity vectors of the `alpha` - particle and the proton is

The ratio of de - Broglie wavelength of `alpha `- particle to that of

1.	The ratio of de - Broglie wavelength of `alpha `- particle to that of a proton being subjected to the same magnetic field so that the radii of their path are equal to each other assuming the field induction vector `vec(B)` is perpendicular to the velocity vectors of the `alpha` - particle and the proton is
Answer» Correct Answer - B `\|barF\|=\|(-dU)/(dr)\|=momega^(2)r , (mv^(2))/r=momega^(2)r , V=omegar`..(i) `mvr=(nh)/(2pi),V=(nh)/(2pimr)`...(ii) (i) & (ii) `rArr r=[(nh)/(2pimomega)]^(1/2) rArr r prop n^(1/2)` `therefore x=2`

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