The ratio of distances travelled by a body starting from rest with constant acceleration in g^(th) and 8^(th) second is .........

The ratio of distances travelled by a body starting from rest with con

1.	The ratio of distances travelled by a body starting from rest with constant acceleration in g^(th) and 8^(th) second is .........
Answer» `17/15` `8/9` `15/17` `9/8` SOLUTION :Distance COVERED by particle in `n^(th)` second, `X _(n) = v _(0)+ a/2 (2n -1)` `therefore` Distance coverd in `9^(th)` second, `x _(9) =(a)/(2) (2 (9) -1) = (17a)/(2) (because v _(0) =0)` Distance covered in `8^(th)` second, `x _(8) = a/2(2 (8) -1) = (15a )/(2)` `therefore (x _(9))/(x _(8)) = (17a)/(2) xx (2)/(15 a)= (17)/(15)`