The ratio of earth's orbital angular momentum (about the sun) to its mass is 4.4×1015m2/s. The area enclosed by earth's orbit approximately is n×1022 m2. Then n is (Answer upto two decimal places)

The ratio of earth's orbital angular momentum (about the sun) to its m

1.	The ratio of earth's orbital angular momentum (about the sun) to its mass is 4.4×1015m2/s. The area enclosed by earth's orbit approximately is n×1022 m2. Then n is (Answer upto two decimal places)
Answer» The ratio of earth's orbital angular momentum (about the sun) to its mass is $4.4 \times 10^{15} m^{2} / s$ . The area enclosed by earth's orbit approximately is $n \times 10^{22}$ $m^{2}$ . Then $n$ is (Answer upto two decimal places)

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The ratio of earth's orbital angular momentum (about the sun) to its mass is 4.4×1015m2/s. The area enclosed by earth's orbit approximately is n×1022 m2. Then n is (Answer upto two decimal places)

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