The ratio of mass percent of C and H of an organic compound (C_xH_yO_z) is 6 : 1. If one molecule of the above compound (C_xH_yO_z) contains half as much oxygen as required to burn one molecule of compound C_xH_y completely to CO_(2) and H_2O. The empirical formula of compound C_xH_yO_z is:

The ratio of mass percent of C and H of an organic compound (C_xH_yO_z

1.	The ratio of mass percent of C and H of an organic compound (C_xH_yO_z) is 6 : 1. If one molecule of the above compound (C_xH_yO_z) contains half as much oxygen as required to burn one molecule of compound C_xH_y completely to CO_(2) and H_2O. The empirical formula of compound C_xH_yO_z is:
Answer» `C_(3)H_(6)O_(3)` `C_(2)H_(4)O` `C_(3)H_(3)O_(2)` `C_(2)H_(4)O_(3)` Answer :D