The ratio of masses of oxygen and nitrogen in a particular gaseous mix – InterviewSolution

1.	The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is
Answer» `1 : 4` `7 : 32` `1 : 8` `3 : 16` Solution :`(n_(O_(2)))/(n_(N_(2))) = (((m_(O_(2))))/((M_(O_(2)))))/(((m_(N_(2))))/((M_(n_(2)))))` `= ((m_(O_(2)))/(m_(N_(2)))) (28)/(32) = (1)/(4) xx (28)/(32)` `= (7)/(32)`

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