1.

The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1:4. The ratio of the number of their molecules is

Answer»

`3:16`
`1:4`
`7:32`
`1:8`

SOLUTION :Suppose the mass of `O_(2)` in the mixture = x G
Then, mass of `N_(2)` in the mixture = 4 x g
No. of moles of `O_(2)=(x)/(32)`
No. of moles of `N_(2)=(4X)/(28)`
As molecules are in the RATIO of their moles, ratio of their molecules is
`O_(2):N_(2)=(x)/(32):(4x)/(28)=(1)/(32):(1)/(7)=7:32`


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