1.

The ratio of moment of inertia about axis of a ring to a axis of disc of same mass and radius is …………….

Answer»

`1:1`
`2:1`
`4:1`
`1:2`

Solution :The MOMENT of inertia RING about an axis PASSING through its centre and perpendicular to its plane is `I_("ring")=MR^(2)`. Where M = mass R = RADIUS.
Moment of inertia disc about on axis passing through its center and perpendicular to its plane
`I_("disc")=(1)/(2)MR^(2)`
`therefore (I_("ring"))/(I_("disc"))=(MR^(2))/((1)/(2)MR^(2))=2:11`


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