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The ratio of moment of inertia about axis of a ring to a axis of disc of same mass and radius is ……………. |
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Answer» `1:1` Moment of inertia disc about on axis passing through its center and perpendicular to its plane `I_("disc")=(1)/(2)MR^(2)` `therefore (I_("ring"))/(I_("disc"))=(MR^(2))/((1)/(2)MR^(2))=2:11` |
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