The ratio of number of oxygen atoms (O) in 16.0 g ozone (O_(3)), 28.0 – InterviewSolution

1.	The ratio of number of oxygen atoms (O) in 16.0 g ozone (O_(3)), 28.0 g carbon monoxide (CO) and 16.0 g oxygen (O_(2)) is :- (Atomic mass : C = 12, O = 16 and Avogadro's constant N_(A) = 6.0 xx 10^(23) mol^(-1))
Answer» `3 : 1 : 1` `1 : 1 : 2` `3 : 1 : 2` `1 : 1 : 1` ANSWER :D

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