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The ratio of P to V at any instant is constant and is equal to 1. for a monoatomic ideal gas undergoing a process. What is the molar heat capacity of the gas?A. `(3R)/2`B. `(4R)/2`C. `(5R)/2`D. `0` |
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Answer» Correct Answer - B From first law of Thermodynamics , `DeltaE=q+w implies nC_vdT=nCdT-PdV` .. (1) Now according to process , P=V and according to ideal gas equation , PV=nRT We have , `V^2=nRT` On differentiating , 2VdV=nRdT and PdV=VdV=`(nRdT)/2` So from first equation we have, `nC_vdT=nCdT-(nRdT)/2` So, `C_v=C-R/2` Hence C`=(4R)/2` |
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