The ratio of rates of diffusion of two gases x and y under similar conditions is 2:1. What will be the ratio of their average speeds if gas X is at -23^@C and gas y is at 273^@C?

The ratio of rates of diffusion of two gases x and y under similar con

1.	The ratio of rates of diffusion of two gases x and y under similar conditions is 2:1. What will be the ratio of their average speeds if gas X is at -23^@C and gas y is at 273^@C?
Answer» Solution :RATIO of rates of diffusion ` (r_(x))/(r_(y)) = SQRT((M_(y))/(M_(x))) = 2 (or) (M_(y))/(M_(x)) = 4` Ratio of average SPEEDS is given as, ` (barC_(X))/(C_(y)) = sqrt((T_(X))/(T_(y))(M_(y))/(M_(x)))` substituting the VALUES, the ratio of speeds ` = sqrt((250)/(500 XX 4) = sqrt(2) : 1 = 1.414 : 1 (or) 1 : 707`