The ratio of rotational kinetic energy to the total kinetic energy of

1.	The ratio of rotational kinetic energy to the total kinetic energy of a diatomic molecule is :
Answer» `3/5` `2/5` `2/3` `5/2` SOLUTION :For diatomic molecule , number of rotational degrees of freedom = 2. Rotational K.E =`2 XX(1/2kT)` = KT TOTAL number of degrees of freedom = 5 `:.` Total K.E `=5(1/2kT) =5/2kT` `:.("RotationalK.E")/("Total K.E")=(kT)/(5//2kT) =2/5`

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