Saved Bookmarks
| 1. |
The ratio of speeds of diffusion of two gases A and B is 1:4. If the mass ratio of A to B present in the given mixture is 2:1, then which of the following is the ratio mole-fraction of A to B? |
|
Answer» `2:3` `(1)/(4)=(m_(A)//M_(A))/(m_(B)//M_(B))sqrt((M_(B))/(M_(A)))` `(1)/(4)=(m_(A))/(m_(B))((M_(B))/(M_(A)))^(3//2)` `(1)/(4)=(2)/(1)((M_(B))/(M_(A)))^(3//2)` `((M_(B))/(M_(A)))(8)^(2//3)=(1)/(4)` `(n_(A))/(n_(B))=(m_(A))/(m_(B))XX(M_(B))/(M_(A))=(2)/(1)xx(1)/(4)` =1:2 |
|