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The ratio of `t_(0.75)` and `t_(0.5)` for first order reaction :-A. `4:3`B. `3:2`C. `2:1`D. `1:2`

Answer» Correct Answer - C
`(t_(0.75))/(t_(0.50))=((2.3)/(k)log(A_(0)/(0.25A_(0))))/((2.3)/(k)log(A_(0)/(0.5A_(0))))=(log(4))/(log2)=(2)/(1)`


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