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The ratio of the energy of a photon with λ = 150 nm to that with λ = 300 nm is (a) 2 (b) \(\frac{1}{4}\)(c) 2 (d)\(\frac{1}{2}\) |
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Answer» (a) 2 \(\frac{E_1}{E_2}\) = \(\frac{λ_2}{λ_1}\) = \(\frac{300}{150}\)= 2 |
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