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The ratio of the largest to shortest wavelength in Balmer series of hydrogen spectra is,A. `(25)/(9)`B. `(17)/(6)`C. `(9)/(5)`D. `(5)/(4)` |
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Answer» Correct Answer - C `" " lambdaprop(1)/((1/(n_(f^(2)))-1/n_(i^(2))))` `" " (lambda_("longest"))/(lambda_("shortest"))=(((1)/(4)-(1)/(oo)))/((1/(4)-(1)/(9)))=((1//4))/((5//36))=(9)/(5)` |
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