1.

The ratio of the number of moles of AgNO_(3), Pb(NO_(3))_(2) and Fe(NO_(3))_(3) required for coagulation of a definite amount of a colloidal sol of silver iodide prepared by mixing AgNO_(3) with excess of KI will be

Answer»

`1:2:3`
`3:2:1`
`6:3:2`
`2:3:6`

Solution :With excess of KI, colloidal particles will be `[AgI]I^(-)`
`underset(1 "mol")([AgI]I^(-)) + underset("1 mol")(AgNO_(3)) to AgI darr + AgI darr + NO_(3)^(-)`
`underset("2 mol")underset("2 mol")(2[AgI]I^(-)) + underset("1/2 mol")underset(1"mol")(Pb(NO_(3))_(2)) to 2AgI darr + PbI_(2) darr + 2NO_(3)^(-)`
`underset(1 "mol")underset(2 "mol")(3[AgI]I^(-)) + underset(1/3 "mol")underset( 1 "mol")(Fe(NO_(3))_(3)) to 3AgI darr + FeI_(3) darr + 3NO_(3)^(+)`
`therefore ` Molar ratio REQUIRED for COAGULATION of same AMOUNTOF `[AgI]I^(-)` is `=1 :1/3 :1/3=6:3:2`


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